W^3+3w^2-25w-75=0

Solution for W^3+3w^2-25w-75=0 equation:

^3+3W^2-25W-75=0

We add all the numbers together, and all the variables

3W^2-25W=0

a = 3; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·3·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$W_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$W_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$W_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*3}=\frac{0}{6}
=0
$
$W_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*3}=\frac{50}{6}
=8+1/3
$